What is (\partial)/(\partial z)(2xy+z^2) ?

The answer to (\partial)/(\partial z)(2xy+z^2) is 2z

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(\partial)/(\partial z)(2xy+z^2)

\frac{\partial}{\partial z} (2 x y + z^{2})

2 z

Solution steps

\frac{\partial}{\partial z} (2 x y + z^{2})

Treat

x, y

as constants

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{\partial}{\partial z} (2 x y) + \frac{\partial}{\partial z} (z^{2})

\frac{\partial}{\partial z} (2 x y) = 0

\frac{\partial}{\partial z} (z^{2}) = 2 z

= 0 + 2 z

Simplify

= 2 z

\frac{\partial}{\partial y} (y x^{2})

\int x (x - 2021) d x

\frac{d}{d x} (3 sin (x) + 3 x cos (x))

\frac{\partial}{\partial x} (sin (π) x)

\frac{m + 2}{m ^{2} + 5 m + 6}

What is (\partial)/(\partial z)(2xy+z^2) ?
The answer to (\partial)/(\partial z)(2xy+z^2) is 2z