What is the integral of tan(6x)sec^2(6x) ?

The integral of tan(6x)sec^2(6x) is 1/12 tan^2(6x)+C

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integral of tan(6x)sec^2(6x)

\int tan (6 x) sec^{2} (6 x) d x

\frac{1}{12} tan^{2} (6 x) + C

Solution steps

\int tan (6 x) sec^{2} (6 x) d x

Apply u-substitution

: \int \frac{u}{6} d u

= \int \frac{u}{6} d u

Take the constant out:

\int a \cdot f (x) d x = a \cdot \int f (x) d x

= \frac{1}{6} \cdot \int u d u

Apply the Power Rule

: \frac{u ^{2}}{2}

= \frac{1}{6} \cdot \frac{u ^{2}}{2}

Substitute back

u = tan (6 x)

= \frac{1}{6} \cdot \frac{tan ^{2} ( 6 x )}{2}

Simplify

\frac{1}{6} \cdot \frac{tan ^{2} ( 6 x )}{2} : \frac{1}{12} tan^{2} (6 x)

= \frac{1}{12} tan^{2} (6 x)

Add a constant to the solution

= \frac{1}{12} tan^{2} (6 x) + C

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What is the integral of tan(6x)sec^2(6x) ?
The integral of tan(6x)sec^2(6x) is 1/12 tan^2(6x)+C