What is the derivative of (2x^2-4)^3 ?

The derivative of (2x^2-4)^3 is 12x(2x^2-4)^2

What is the first derivative of (2x^2-4)^3 ?

The first derivative of (2x^2-4)^3 is 12x(2x^2-4)^2

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derivative of

(2 x^{2} - 4)^{3}

12 x (2 x^{2} - 4)^{2}

Solution steps

\frac{d}{d x} ((2 x^{2} - 4)^{3})

Apply the chain rule:

3 (2 x^{2} - 4)^{2} \frac{d}{d x} (2 x^{2} - 4)

= 3 (2 x^{2} - 4)^{2} \frac{d}{d x} (2 x^{2} - 4)

\frac{d}{d x} (2 x^{2} - 4) = 4 x

= 3 (2 x^{2} - 4)^{2} \cdot 4 x

Simplify

= 12 x (2 x^{2} - 4)^{2}

x \to 0 - lim (\frac{cot ( π x ) sin ( x )}{2 sec ( x )})

n = 0 \sum \infty 2 n - 1

\frac{\partial}{\partial x} (\frac{y}{x ( x + y )})

x \to 7 lim (\frac{x + 8}{x - 7})

\int - \frac{1}{\frac{2}{x} y} d y

What is the derivative of (2x^2-4)^3 ?
The derivative of (2x^2-4)^3 is 12x(2x^2-4)^2
What is the first derivative of (2x^2-4)^3 ?
The first derivative of (2x^2-4)^3 is 12x(2x^2-4)^2