What is the integral of (x/5)^2 ?

The integral of (x/5)^2 is (x^3)/(25)-(2x^3)/(75)+C

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integral of (x/5)^2

\int (\frac{x}{5})^{2} d x

\frac{x ^{3}}{25} - \frac{2 x ^{3}}{75} + C

Solution steps

\int (\frac{x}{5})^{2} d x

Apply Integration By Parts

: \frac{x ^{3}}{25} - \int \frac{2 x ^{2}}{25} d x

= \frac{x ^{3}}{25} - \int \frac{2 x ^{2}}{25} d x

\int \frac{2 x ^{2}}{25} d x = \frac{2 x ^{3}}{75}

= \frac{x ^{3}}{25} - \frac{2 x ^{3}}{75}

Add a constant to the solution

= \frac{x ^{3}}{25} - \frac{2 x ^{3}}{75} + C

\frac{d}{d x} (- 3 cos (x) + 2 sin (x))

\frac{d y}{d t} = y (1 - y)

\frac{d}{d t} (2 t)

\int_{1}^{3} 4 x^{4} ln (x) d x

\frac{d}{d x} (x - 2 x)

What is the integral of (x/5)^2 ?
The integral of (x/5)^2 is (x^3)/(25)-(2x^3)/(75)+C