What is the solution for 10(t+1)(dy)/(dt)-9y=9t ?

The solution for 10(t+1)(dy)/(dt)-9y=9t is y=9t+10+c_{1}(t+1)^{9/10}

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10(t+1)(dy)/(dt)-9y=9t

10 (t + 1) \frac{d y}{d t} - 9 y = 9 t

y = 9 t + 10 + c_{1} (t + 1)^{\frac{9}{10}}

Solution steps

10 (t + 1) \frac{d y}{d t} - 9 y = 9 t

Solve linear ODE:

y = 9 t + 10 + c_{1} (t + 1)^{\frac{9}{10}}

y = 9 t + 10 + c_{1} (t + 1)^{\frac{9}{10}}

x \to 0 lim (\frac{- cos ( x ) + 1}{x})

\frac{d}{d x} (\frac{x - 5}{( x - 3 ) ( x - 1 )})

x \to 0 lim (x sin (\frac{9}{x}))

\int sin^{5} (\frac{x}{3}) cos (\frac{x}{3}) d x

\frac{\partial}{\partial x} (z cos (y x))

What is the solution for 10(t+1)(dy)/(dt)-9y=9t ?
The solution for 10(t+1)(dy)/(dt)-9y=9t is y=9t+10+c_{1}(t+1)^{9/10}