What is the derivative of f(x)=x^2(1-3x) ?

The derivative of f(x)=x^2(1-3x) is 2x-9x^2

What is the first derivative of f(x)=x^2(1-3x) ?

The first derivative of f(x)=x^2(1-3x) is 2x-9x^2

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derivative of

f (x) = x^{2} (1 - 3 x)

2 x - 9 x^{2}

Solution steps

\frac{d}{d x} (x^{2} (1 - 3 x))

Apply the Product Rule:

(f \cdot g)^{'} = f^{'} \cdot g + f \cdot g^{'}

f = x^{2}, g = 1 - 3 x

= \frac{d}{d x} (x^{2}) (1 - 3 x) + \frac{d}{d x} (1 - 3 x) x^{2}

\frac{d}{d x} (x^{2}) = 2 x

\frac{d}{d x} (1 - 3 x) = - 3

= 2 x (1 - 3 x) + (- 3) x^{2}

Simplify

2 x (1 - 3 x) + (- 3) x^{2} : 2 x - 9 x^{2}

= 2 x - 9 x^{2}

e^{θ}

y = ln (1 + x)

\int \frac{48 x ^{2}}{( x - 18 ) ( x + 6 ) ^{2}} d x

\int - 2 sin (t) d t

\frac{d}{d r} (π r^{2} h)

What is the derivative of f(x)=x^2(1-3x) ?
The derivative of f(x)=x^2(1-3x) is 2x-9x^2
What is the first derivative of f(x)=x^2(1-3x) ?
The first derivative of f(x)=x^2(1-3x) is 2x-9x^2