What is the integral of ((x-1))/(x^2+5x+6) ?

The integral of ((x-1))/(x^2+5x+6) is -3ln|x+2|+4ln|x+3|+C

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integral of ((x-1))/(x^2+5x+6)

\int \frac{( x - 1 )}{x ^{2} + 5 x + 6} d x

- 3 ln ∣ x + 2 ∣ + 4 ln ∣ x + 3 ∣ + C

Solution steps

\int \frac{x - 1}{x ^{2} + 5 x + 6} d x

Take the partial fraction of

\frac{x - 1}{x ^{2} + 5 x + 6} : - \frac{3}{x + 2} + \frac{4}{x + 3}

= \int - \frac{3}{x + 2} + \frac{4}{x + 3} d x

Apply the Sum Rule:

\int f (x) \pm g (x) d x = \int f (x) d x \pm \int g (x) d x

= - \int \frac{3}{x + 2} d x + \int \frac{4}{x + 3} d x

\int \frac{3}{x + 2} d x = 3 ln ∣ x + 2 ∣

\int \frac{4}{x + 3} d x = 4 ln ∣ x + 3 ∣

= - 3 ln ∣ x + 2 ∣ + 4 ln ∣ x + 3 ∣

Add a constant to the solution

= - 3 ln ∣ x + 2 ∣ + 4 ln ∣ x + 3 ∣ + C

y^{^{''}} - \frac{5}{t} y^{^{'}} + \frac{25}{t ^{2}} y = 0

\int 12 x d x

\int (1 - 3 x)^{\frac{1}{3}} d x

x \to π lim (tan (\frac{2}{3} x))

f (x) = \frac{x ^{2}}{2 + x}

What is the integral of ((x-1))/(x^2+5x+6) ?
The integral of ((x-1))/(x^2+5x+6) is -3ln|x+2|+4ln|x+3|+C