What is (\partial)/(\partial x)(ln(x)-4) ?

The answer to (\partial)/(\partial x)(ln(x)-4) is 1/x

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(\partial)/(\partial x)(ln(x)-4)

\frac{\partial}{\partial x} (ln (x) - 4)

\frac{1}{x}

Solution steps

\frac{\partial}{\partial x} (ln (x) - 4)

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{\partial}{\partial x} (ln (x)) - \frac{\partial}{\partial x} (4)

\frac{\partial}{\partial x} (ln (x)) = \frac{1}{x}

\frac{\partial}{\partial x} (4) = 0

= \frac{1}{x} - 0

Simplify

= \frac{1}{x}

\frac{d}{d x} (y^{5} sin (5 x))

\frac{\partial}{\partial x} (4 sin (4 x) e^{3 x})

n = 1 \sum \infty \frac{5}{4 ^{n - 1}}

\frac{\partial}{\partial y} (e^{x^{2} + y^{2}})

k = 1 \sum \infty e^{- k}

What is (\partial)/(\partial x)(ln(x)-4) ?
The answer to (\partial)/(\partial x)(ln(x)-4) is 1/x