What is the solution for 10y^'+5y=8e^{6x},y(0)=9 ?

The solution for 10y^'+5y=8e^{6x},y(0)=9 is y=(8e^{6x})/(65)+(577)/(65e^{x/2)}

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10y^'+5y=8e^{6x},y(0)=9

10 y^{^{'}} + 5 y = 8 e^{6 x}, y (0) = 9

y = \frac{8 e ^{6 x}}{65} + \frac{577}{65 e ^{\frac{x}{2}}}

Solution steps

10 y^{'} (x) + 5 y = 8 e^{6 x}

Solve linear ODE:

y = \frac{8 e ^{6 x}}{65} + \frac{577}{65 e ^{\frac{x}{2}}}

y = \frac{8 e ^{6 x}}{65} + \frac{577}{65 e ^{\frac{x}{2}}}

x \to 3 lim (\frac{∣ x ∣ - x}{3 - x})

y^{^{''}} + (y^{^{'}})^{2} + 1 = 0

\int_{- 40}^{0} \frac{1}{9 - x} d x

y = 30 e^{- 0.0000323 x}

\frac{1}{8} x, 8 x, \frac{2}{x}

What is the solution for 10y^'+5y=8e^{6x},y(0)=9 ?
The solution for 10y^'+5y=8e^{6x},y(0)=9 is y=(8e^{6x})/(65)+(577)/(65e^{x/2)}