What is the solution for (dy)/(dx)+((1-y^2)/(1-x^2))^{1/2}=0 ?

The solution for (dy)/(dx)+((1-y^2)/(1-x^2))^{1/2}=0 is y=sin(-arcsin(x)+c_{1})

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(dy)/(dx)+((1-y^2)/(1-x^2))^{1/2}=0

\frac{d y}{d x} + (\frac{1 - y ^{2}}{1 - x ^{2}})^{\frac{1}{2}} = 0

y = sin (- arcsin (x) + c_{1})

Solution steps

\frac{d y}{d x} + (\frac{1 - y ^{2}}{1 - x ^{2}})^{\frac{1}{2}} = 0

Solve separable ODE:

y = sin (- arcsin (x) + c_{1})

y = sin (- arcsin (x) + c_{1})

\frac{d y}{d x} = 9 y

G (t) = \frac{1 - 3 t}{4 + t}

\int \frac{x ^{2}}{5 x ^{3} + 8} d x

f (x) = 3 e^{x} + x, (0, 3)

\int (7 x (x^{6} - \frac{1}{7})) d x

What is the solution for (dy)/(dx)+((1-y^2)/(1-x^2))^{1/2}=0 ?
The solution for (dy)/(dx)+((1-y^2)/(1-x^2))^{1/2}=0 is y=sin(-arcsin(x)+c_{1})