What is the tangent of g(x)=-3x^2+5x-6 ?

The tangent of g(x)=-3x^2+5x-6 is y=(-6a_{0}+5)x+3a_{0}^2-6

Popular >

tangent of g(x)=-3x^2+5x-6

tangent of

g (x) = - 3 x^{2} + 5 x - 6

y = (- 6 a_{0} + 5) x + 3 a_{0}^{2} - 6

Solution steps

Compute the tangent line to the general point

x = a_{0}

Find the tangent point:

(a_{0}, - 3 a_{0}^{2} + 5 a_{0} - 6)

Find the slope of

g (x) = - 3 x^{2} + 5 x - 6 : \frac{d g ( x )}{d x} = - 6 x + 5

EN : T i tl e G e n er a l Eq u a t i o n Sl o p e A t P o in t 2 Eq : m = - 6 a_{0} + 5

Find the line with slope m=

- 6 a_{0} + 5

and passing through

(a_{0}, - 3 a_{0}^{2} + 5 a_{0} - 6) : y = (- 6 a_{0} + 5) x + 3 a_{0}^{2} - 6

y = (- 6 a_{0} + 5) x + 3 a_{0}^{2} - 6

6 x

\int \frac{( x - 1 )}{2} d x

(8 + x) y^{^{'}} = 7 y

\frac{\partial}{\partial x} (ln (x^{2} + y^{4}) - z)

\frac{\partial}{\partial x} (\frac{2 y}{9 x ^{2} + y ^{2} + 9})

What is the tangent of g(x)=-3x^2+5x-6 ?
The tangent of g(x)=-3x^2+5x-6 is y=(-6a_{0}+5)x+3a_{0}^2-6