What is the tangent of y=3x-2x^2,(-3,-27) ?

The tangent of y=3x-2x^2,(-3,-27) is y=15x+18

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

tangent of y=3x-2x^2,(-3,-27)

tangent of

y = 3 x - 2 x^{2}, (- 3, - 27)

y = 15 x + 18

Solution steps

Find the slope of

y = 3 x - 2 x^{2} : \frac{d y}{d x} = 3 - 4 x

EN : T i tl e G e n er a l Eq u a t i o n Sl o p e A t P o in t 2 Eq : m = 15

Find the line with slope m=

15

and passing through

(- 3, - 27) : y = 15 x + 18

y = 15 x + 18

x \to 0 + lim (x + 1)

\frac{d y}{d x} = e^{2 y} sin (x)

\int x - 6 cos (x) d x

n = 1 \sum \infty \frac{x ^{n}}{1 0 ^{n}}

\int_{0}^{1} 36 t^{2} + 9 t^{4} d t

What is the tangent of y=3x-2x^2,(-3,-27) ?
The tangent of y=3x-2x^2,(-3,-27) is y=15x+18