What is the tangent of f(x)=3xcos(x),\at x=pi ?

The tangent of f(x)=3xcos(x),\at x=pi is y=-3x

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tangent of f(x)=3xcos(x),\at x=pi

tangent of

f (x) = 3 x cos (x), at x = π

y = - 3 x

Solution steps

Find the tangent point:

(π, - 3 π)

Find the slope of

f (x) = 3 x cos (x) : \frac{df ( x )}{d x} = 3 (cos (x) - x sin (x))

EN : T i tl e G e n er a l Eq u a t i o n Sl o p e A t P o in t 2 Eq : m = - 3

Find the line with slope m=

- 3

and passing through

(π, - 3 π) : y = - 3 x

y = - 3 x

\frac{\partial}{\partial x} (x^{2} + 3)

9 y^{^{''}} + 9 y = 0

3 x^{2} e^{x} + e^{x} (x^{3} + 9)

f (x) = \frac{cos ( x )}{x ^{2} - 1}

f (x) = \frac{( 4 x ^{2} - \frac{1}{2} x )}{( 9 x + 8 )}

What is the tangent of f(x)=3xcos(x),\at x=pi ?
The tangent of f(x)=3xcos(x),\at x=pi is y=-3x