What is the solution for (2xy)dx+(1-x^2)dy=0 ?

The solution for (2xy)dx+(1-x^2)dy=0 is y=e^{c_{1}}-e^{c_{1}}x^2

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

(2xy)dx+(1-x^2)dy=0

(2 x y) d x + (1 - x^{2}) d y = 0

y = e^{c_{1}} - e^{c_{1}} x^{2}

Solution steps

(2 x y) d x + (1 - x^{2}) d y = 0

Solve separable ODE:

y = e^{c_{1}} - e^{c_{1}} x^{2}

y = e^{c_{1}} - e^{c_{1}} x^{2}

f (x) = (11 x + 2) x^{2}

x \to \infty lim (\frac{ln ( x ) + x ^{3}}{e ^{- x}})

n = 0 \sum \infty \frac{9}{3 ^{n - 1}}

x \to 2 lim (x^{2} - 43 - x + 7)

\frac{d}{d x} (ln (x + \frac{1}{x}))

What is the solution for (2xy)dx+(1-x^2)dy=0 ?
The solution for (2xy)dx+(1-x^2)dy=0 is y=e^{c_{1}}-e^{c_{1}}x^2