What is the solution for y^'+2y= 1/x ?

The solution for y^'+2y= 1/x is y=(\Ei(2x))/(e^{2x)}+(c_{1})/(e^{2x)}

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y^'+2y= 1/x

y^{^{'}} + 2 y = \frac{1}{x}

y = \frac{Ei ( 2 x )}{e ^{2 x}} + \frac{c _{1}}{e ^{2 x}}

Solution steps

y^{'} (x) + 2 y = \frac{1}{x}

Solve linear ODE:

y = \frac{Ei ( 2 x )}{e ^{2 x}} + \frac{c _{1}}{e ^{2 x}}

y = \frac{Ei ( 2 x )}{e ^{2 x}} + \frac{c _{1}}{e ^{2 x}}

y^{^{'}} + y = x^{2} y^{2}

\frac{d}{d x} (lo g_{5} (x^{2}))

\int \frac{4 w - 11}{2 w ^{2} + 7 w - 4} d w

\int \frac{1}{3 x ^{2} + 4 x + 1} d x

\int_{- 1}^{1} 1 1^{x} d x

What is the solution for y^'+2y= 1/x ?
The solution for y^'+2y= 1/x is y=(\Ei(2x))/(e^{2x)}+(c_{1})/(e^{2x)}