What is (\partial)/(\partial y)(2x^4yz^3) ?

The answer to (\partial)/(\partial y)(2x^4yz^3) is 2x^4z^3

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

(\partial)/(\partial y)(2x^4yz^3)

\frac{\partial}{\partial y} (2 x^{4} y z^{3})

2 x^{4} z^{3}

Solution steps

\frac{\partial}{\partial y} (2 x^{4} y z^{3})

Treat

x, z

as constants

Take the constant out:

(a \cdot f)^{'} = a \cdot f^{'}

= 2 x^{4} z^{3} \frac{\partial}{\partial y} (y)

Apply the common derivative:

\frac{\partial}{\partial y} (y) = 1

= 2 x^{4} z^{3} \cdot 1

Simplify

= 2 x^{4} z^{3}

cos (2 x)

\frac{d}{d x} (\frac{x y}{x ^{2} + y ^{2} + z ^{2}})

f (x) = ln ((2 x - 5) (3 x^{2} - 5))

\int cos^{3} (6 x) sin^{2} (6 x) d x

\int \frac{3 e ^{2 x}}{e ^{2 x} + 11 e ^{x} + 28} d x

What is (\partial)/(\partial y)(2x^4yz^3) ?
The answer to (\partial)/(\partial y)(2x^4yz^3) is 2x^4z^3