What is the derivative of-\sqrt[3]{x^5} ?

The derivative of-\sqrt[3]{x^5} is -(5x^4)/(3(x^5)^{2/3)}

What is the first derivative of-\sqrt[3]{x^5} ?

The first derivative of-\sqrt[3]{x^5} is -(5x^4)/(3(x^5)^{2/3)}

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derivative of

- \frac{5 x ^{4}}{3 ( x ^{5} ) ^{\frac{2}{3}}}

Solution steps

Take the constant out:

(a \cdot f)^{'} = a \cdot f^{'}

Apply the chain rule:

\frac{1}{3 ( x ^{5} ) ^{\frac{2}{3}}} \frac{d}{d x} (x^{5})

= \frac{1}{3 ( x ^{5} ) ^{\frac{2}{3}}} \frac{d}{d x} (x^{5})

\frac{d}{d x} (x^{5}) = 5 x^{4}

= - \frac{1}{3 ( x ^{5} ) ^{\frac{2}{3}}} \cdot 5 x^{4}

Simplify

- \frac{1}{3 ( x ^{5} ) ^{\frac{2}{3}}} \cdot 5 x^{4} : - \frac{5 x ^{4}}{3 ( x ^{5} ) ^{\frac{2}{3}}}

= - \frac{5 x ^{4}}{3 ( x ^{5} ) ^{\frac{2}{3}}}

y = e^{x}, y = e^{- x}, x = - 2, x = 1

\int \frac{3 π}{2} cos (\frac{3 π x}{2}) d x

\frac{d}{d x} (arcsec (3 x + 2))

x \to \frac{7 π}{2} - lim (sec (x))

f (x) = \frac{2 x}{3 - 4 x ^{3}}, at x = \frac{1}{2}

What is the derivative of-\sqrt[3]{x^5} ?
The derivative of-\sqrt[3]{x^5} is -(5x^4)/(3(x^5)^{2/3)}
What is the first derivative of-\sqrt[3]{x^5} ?
The first derivative of-\sqrt[3]{x^5} is -(5x^4)/(3(x^5)^{2/3)}