What is the derivative of x^4+2x^2-x ?

The derivative of x^4+2x^2-x is 4x^3+4x-1

What is the first derivative of x^4+2x^2-x ?

The first derivative of x^4+2x^2-x is 4x^3+4x-1

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\frac{d}{d x} (x^{4} + 2 x^{2} - x)

4 x^{3} + 4 x - 1

Solution steps

\frac{d}{d x} (x^{4} + 2 x^{2} - x)

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d x} (x^{4}) + \frac{d}{d x} (2 x^{2}) - \frac{d x}{d x}

\frac{d}{d x} (x^{4}) = 4 x^{3}

\frac{d}{d x} (2 x^{2}) = 4 x

\frac{d x}{d x} = 1

= 4 x^{3} + 4 x - 1

\frac{\partial}{\partial x} (1 x)

(1 + y) \frac{d y}{d t} = 6 t, y (2) = 5

\int \frac{x ^{2} - 2}{x + 3} d x

\int \frac{( x + 1 )}{x ^{2} + 2 x} d x

\frac{d}{d x} (\frac{( x - 3 ) ( 3 x - 25 )}{x})

What is the derivative of x^4+2x^2-x ?
The derivative of x^4+2x^2-x is 4x^3+4x-1
What is the first derivative of x^4+2x^2-x ?
The first derivative of x^4+2x^2-x is 4x^3+4x-1