What is the derivative of 3x^2-x^{3x} ?

The derivative of 3x^2-x^{3x} is 6x-3x^{3x}(ln(x)+1)

What is the first derivative of 3x^2-x^{3x} ?

The first derivative of 3x^2-x^{3x} is 6x-3x^{3x}(ln(x)+1)

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\frac{d}{d x} (3 x^{2} - x^{3 x})

6 x - 3 x^{3 x} (ln (x) + 1)

Solution steps

\frac{d}{d x} (3 x^{2} - x^{3 x})

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d x} (3 x^{2}) - \frac{d}{d x} (x^{3 x})

\frac{d}{d x} (3 x^{2}) = 6 x

\frac{d}{d x} (x^{3 x}) = 3 x^{3 x} (ln (x) + 1)

= 6 x - 3 x^{3 x} (ln (x) + 1)

\frac{\partial}{\partial x} ((2 x + 8 y)^{3})

\frac{d}{d x} (x^{- 1} ln (x))

y^{^{'}} = y (x y^{4} + 4)

\frac{d}{d x} (\frac{x y}{x y})

\frac{d}{d x} (6 sin^{2} (x))

What is the derivative of 3x^2-x^{3x} ?
The derivative of 3x^2-x^{3x} is 6x-3x^{3x}(ln(x)+1)
What is the first derivative of 3x^2-x^{3x} ?
The first derivative of 3x^2-x^{3x} is 6x-3x^{3x}(ln(x)+1)