What is the derivative of 7/(\sqrt[4]{x)} ?

The derivative of 7/(\sqrt[4]{x)} is -7/(4x^{5/4)}

What is the first derivative of 7/(\sqrt[4]{x)} ?

The first derivative of 7/(\sqrt[4]{x)} is -7/(4x^{5/4)}

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derivative of

- \frac{7}{4 x ^{\frac{5}{4}}}

Solution steps

Take the constant out:

(a \cdot f)^{'} = a \cdot f^{'}

Apply exponent rule:

\frac{1}{a} = a^{- 1}

= 7 \frac{d}{d x} (x^{- \frac{1}{4}})

Apply the Power Rule:

\frac{d}{d x} (x^{a}) = a \cdot x^{a - 1}

= 7 (- \frac{1}{4} x^{- \frac{1}{4} - 1})

Simplify

7 (- \frac{1}{4} x^{- \frac{1}{4} - 1}) : - \frac{7}{4 x ^{\frac{5}{4}}}

= - \frac{7}{4 x ^{\frac{5}{4}}}

y^{^{''}} + 7 y^{^{'}} + 12 = 0

cos (x), - 0.25

x \to 2 + lim (\frac{1}{x})

\int 6 sin^{5} (x) d x

(csc (x))^{^{'}}

What is the derivative of 7/(\sqrt[4]{x)} ?
The derivative of 7/(\sqrt[4]{x)} is -7/(4x^{5/4)}
What is the first derivative of 7/(\sqrt[4]{x)} ?
The first derivative of 7/(\sqrt[4]{x)} is -7/(4x^{5/4)}