What is the d/(dy)(x^3+3xy^2-15x-12y) ?

The d/(dy)(x^3+3xy^2-15x-12y) is 6xy-12

What is the first d/(dy)(x^3+3xy^2-15x-12y) ?

The first d/(dy)(x^3+3xy^2-15x-12y) is 6xy-12

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\frac{d}{d y} (x^{3} + 3 x y^{2} - 15 x - 12 y)

6 x y - 12

Solution steps

\frac{d}{d y} (x^{3} + 3 x y^{2} - 15 x - 12 y)

Treat

x

as a constant

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d y} (x^{3}) + \frac{d}{d y} (3 x y^{2}) - \frac{d}{d y} (15 x) - \frac{d}{d y} (12 y)

\frac{d}{d y} (x^{3}) = 0

\frac{d}{d y} (3 x y^{2}) = 6 x y

\frac{d}{d y} (15 x) = 0

\frac{d}{d y} (12 y) = 12

= 0 + 6 x y - 0 - 12

Simplify

= 6 x y - 12

- 9.8 t^{2} + 2 t + 1

\frac{d}{d x} (\frac{55}{0.01 x ^{2} + 1})

\frac{\partial}{\partial x} (f (x, y) (\frac{x}{y}))

\frac{d}{d a} (sin^{2} (a) cos^{2} (a))

y^{^{'}} + y = \frac{1}{1 + e ^{2 x}}

What is the d/(dy)(x^3+3xy^2-15x-12y) ?
The d/(dy)(x^3+3xy^2-15x-12y) is 6xy-12
What is the first d/(dy)(x^3+3xy^2-15x-12y) ?
The first d/(dy)(x^3+3xy^2-15x-12y) is 6xy-12