What is the tangent of f(x)=x^2-6,(4,10) ?

The tangent of f(x)=x^2-6,(4,10) is y=8x-22

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tangent of f(x)=x^2-6,(4,10)

tangent of

f (x) = x^{2} - 6, (4, 10)

y = 8 x - 22

Solution steps

Find the slope of

f (x) = x^{2} - 6 : \frac{df ( x )}{d x} = 2 x

EN : T i tl e G e n er a l Eq u a t i o n Sl o p e A t P o in t 2 Eq : m = 8

Find the line with slope m=

8

and passing through

(4, 10) : y = 8 x - 22

y = 8 x - 22

\frac{d ^{2}}{d x ^{2}} (x e^{4 x})

f (x) = \frac{1}{2 x}, at x = 81

\frac{d}{d x} (f (x) (\frac{x ^{4}}{4} - \frac{1}{4}))

lo g_{3} (x - 4 x^{2})

\frac{d}{d x} (\frac{1}{( x ^{3} + 4 ) ^{2}})

What is the tangent of f(x)=x^2-6,(4,10) ?
The tangent of f(x)=x^2-6,(4,10) is y=8x-22