What is the sum from n=0 to infinity of 9((5/12)^n) ?

The sum from n=0 to infinity of 9((5/12)^n) is 108/7

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

sum from n=0 to infinity of 9((5/12)^n)

n = 0 \sum \infty 9 ((\frac{5}{12})^{n})

\frac{108}{7}

Solution steps

n = 0 \sum \infty 9 (\frac{5}{12})^{n}

Apply the constant multiplication rule:

\sum c \cdot a_{n} = c \cdot \sum a_{n}

= 9 \cdot n = 0 \sum \infty (\frac{5}{12})^{n}

Apply Series Geometric Test:

\frac{12}{7}

= 9 \cdot \frac{12}{7}

Simplify

9 \cdot \frac{12}{7} : \frac{108}{7}

= \frac{108}{7}

\int \frac{x ^{6} e ^{x}}{x} d x

\frac{d y}{d x} + 3 x^{2} y = 6 x^{2}

(- 4, - 5), (3, - 5)

\int \frac{sin ( x )}{4 + cos ^{2} ( x )} d x

\int (5 + 2 w^{3} - w^{5}) cos (3 w) d w

What is the sum from n=0 to infinity of 9((5/12)^n) ?
The sum from n=0 to infinity of 9((5/12)^n) is 108/7