What is the d/(dt)(t^3-12t^2+45t) ?

The d/(dt)(t^3-12t^2+45t) is 3t^2-24t+45

What is the first d/(dt)(t^3-12t^2+45t) ?

The first d/(dt)(t^3-12t^2+45t) is 3t^2-24t+45

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\frac{d}{d t} (t^{3} - 12 t^{2} + 45 t)

3 t^{2} - 24 t + 45

Solution steps

\frac{d}{d t} (t^{3} - 12 t^{2} + 45 t)

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d t} (t^{3}) - \frac{d}{d t} (12 t^{2}) + \frac{d}{d t} (45 t)

\frac{d}{d t} (t^{3}) = 3 t^{2}

\frac{d}{d t} (12 t^{2}) = 24 t

\frac{d}{d t} (45 t) = 45

= 3 t^{2} - 24 t + 45

3 t

\int e - x d x

\int sin (6 θ) cos (2 θ) d θ

f (x) = (\frac{2 x}{x ^{2} + 1}), at x = 1

y^{^{''}} = - 3 y

What is the d/(dt)(t^3-12t^2+45t) ?
The d/(dt)(t^3-12t^2+45t) is 3t^2-24t+45
What is the first d/(dt)(t^3-12t^2+45t) ?
The first d/(dt)(t^3-12t^2+45t) is 3t^2-24t+45