What is the solution for xy^'=y+3x^2sin(x),y(pi)=0 ?

The solution for xy^'=y+3x^2sin(x),y(pi)=0 is y=-3xcos(x)-3x

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xy^'=y+3x^2sin(x),y(pi)=0

x y^{^{'}} = y + 3 x^{2} sin (x), y (π) = 0

y = - 3 x cos (x) - 3 x

Solution steps

x y^{'} (x) = y + 3 x^{2} sin (x)

Solve linear ODE:

y = - 3 x cos (x) - 3 x

y = - 3 x cos (x) - 3 x

\int_{2}^{4} \frac{1}{x ^{2} - 25} d x

x \to 0 lim ((4 x)^{7 x})

- 2 x^{2} + x, - 2, 1

n = 0 \sum \infty \frac{1}{2}

\frac{\partial}{\partial x} (a sin (2 x))

What is the solution for xy^'=y+3x^2sin(x),y(pi)=0 ?
The solution for xy^'=y+3x^2sin(x),y(pi)=0 is y=-3xcos(x)-3x