What is the derivative of sqrt(2x+1) ?

The derivative of sqrt(2x+1) is 1/(sqrt(2x+1))

What is the first derivative of sqrt(2x+1) ?

The first derivative of sqrt(2x+1) is 1/(sqrt(2x+1))

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derivative of

2 x + 1

\frac{1}{2 x + 1}

Solution steps

\frac{d}{d x} (2 x + 1)

Apply the chain rule:

\frac{1}{2 2 x + 1} \frac{d}{d x} (2 x + 1)

= \frac{1}{2 2 x + 1} \frac{d}{d x} (2 x + 1)

\frac{d}{d x} (2 x + 1) = 2

= \frac{1}{2 2 x + 1} \cdot 2

Simplify

\frac{1}{2 2 x + 1} \cdot 2 : \frac{1}{2 x + 1}

= \frac{1}{2 x + 1}

\int \frac{2}{cos ^{2} ( x )} d x

y^{^{''}} + y^{^{'}} - 6 y = 0, y (0) = 5, y^{^{'}} (0) = 2

\int 5 x^{2} + 3 x + 2 d x

\int_{0}^{5} (1 + 2 x^{3}) d x

\frac{d}{d x} ((\frac{x ^{2} + 2}{x ^{2} - 2})^{3})

What is the derivative of sqrt(2x+1) ?
The derivative of sqrt(2x+1) is 1/(sqrt(2x+1))
What is the first derivative of sqrt(2x+1) ?
The first derivative of sqrt(2x+1) is 1/(sqrt(2x+1))