What is the solution for (dy)/(dx)=x+2y,y(0)=4 ?

The solution for (dy)/(dx)=x+2y,y(0)=4 is y=-(2x+1)/4+17/4 e^{2x}

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

(dy)/(dx)=x+2y,y(0)=4

\frac{d y}{d x} = x + 2 y, y (0) = 4

y = - \frac{2 x + 1}{4} + \frac{17}{4} e^{2 x}

Solution steps

\frac{d y}{d x} = x + 2 y

Solve linear ODE:

y = - \frac{2 x + 1}{4} + \frac{17}{4} e^{2 x}

y = - \frac{2 x + 1}{4} + \frac{17}{4} e^{2 x}

\int_{0}^{8} x^{2} e^{- 3 x} d x

\int (\frac{8 x ^{4} - 4 x ^{3} - 7 x}{x}) d x

y \frac{d y}{d x} = e^{x}

\frac{\partial}{\partial x} (cos (x^{2}) \cdot sin (z \cdot y))

\frac{\partial}{\partial x} (17 - 2 x^{2} - y^{2})

What is the solution for (dy)/(dx)=x+2y,y(0)=4 ?
The solution for (dy)/(dx)=x+2y,y(0)=4 is y=-(2x+1)/4+17/4 e^{2x}