What is the solution for 2x^2y+x^3(dy)/(dx)=1 ?

The solution for 2x^2y+x^3(dy)/(dx)=1 is y=(ln(x))/(x^2)+(c_{1})/(x^2)

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2x^2y+x^3(dy)/(dx)=1

2 x^{2} y + x^{3} \frac{d y}{d x} = 1

y = \frac{ln ( x )}{x ^{2}} + \frac{c _{1}}{x ^{2}}

Solution steps

2 x^{2} y + x^{3} \frac{d y}{d x} = 1

Solve linear ODE:

y = \frac{ln ( x )}{x ^{2}} + \frac{c _{1}}{x ^{2}}

y = \frac{ln ( x )}{x ^{2}} + \frac{c _{1}}{x ^{2}}

x \to 7 lim (e^{x - 7})

\frac{s}{s ^{2} - 14 s + 1}

t \cdot e^{2 t}

\frac{d y}{d t} + \frac{1}{2} y = \frac{1}{2} e^{\frac{t}{3}}

n = 0 \sum \infty 5 (- \frac{10}{11})^{n}

What is the solution for 2x^2y+x^3(dy)/(dx)=1 ?
The solution for 2x^2y+x^3(dy)/(dx)=1 is y=(ln(x))/(x^2)+(c_{1})/(x^2)