What is the derivative of 3x^6+9x-3 ?

The derivative of 3x^6+9x-3 is 18x^5+9

What is the first derivative of 3x^6+9x-3 ?

The first derivative of 3x^6+9x-3 is 18x^5+9

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\frac{d}{d x} (3 x^{6} + 9 x - 3)

18 x^{5} + 9

Solution steps

\frac{d}{d x} (3 x^{6} + 9 x - 3)

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d x} (3 x^{6}) + \frac{d}{d x} (9 x) - \frac{d}{d x} (3)

\frac{d}{d x} (3 x^{6}) = 18 x^{5}

\frac{d}{d x} (9 x) = 9

\frac{d}{d x} (3) = 0

= 18 x^{5} + 9 - 0

Simplify

= 18 x^{5} + 9

\int_{1}^{5} \frac{1}{x} d x

\frac{\partial}{\partial x} (14 - x^{2} - 4 y)

\frac{d}{d x} (ln (x^{2} + 2 x + 5))

\frac{d}{d x} (4 x csc (x))

\frac{d}{d x} (\frac{- e ^{x} sin ( x )}{cos ( x )})

What is the derivative of 3x^6+9x-3 ?
The derivative of 3x^6+9x-3 is 18x^5+9
What is the first derivative of 3x^6+9x-3 ?
The first derivative of 3x^6+9x-3 is 18x^5+9