What is the derivative of x^2-2xy ?

The derivative of x^2-2xy is 2x-2(y+x(dy)/(dx))

What is the first derivative of x^2-2xy ?

The first derivative of x^2-2xy is 2x-2(y+x(dy)/(dx))

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\frac{d}{d x} (x^{2} - 2 x y)

2 x - 2 (y + x \frac{d y}{d x})

Solution steps

\frac{d}{d x} (x^{2} - 2 x y)

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d x} (x^{2}) - \frac{d}{d x} (2 x y)

\frac{d}{d x} (x^{2}) = 2 x

\frac{d}{d x} (2 x y) = 2 (y + x \frac{d y}{d x})

= 2 x - 2 (y + x \frac{d y}{d x})

\frac{d}{d x} (\frac{k}{x})

x \to 3 lim (\frac{∣ x - 3 ∣}{x - 3})

\frac{d y}{d x} = cot (x)

f (x) = \frac{8}{3} x^{3} - 16 x^{2} + 24 x + 4

\frac{\partial}{\partial x} (3 + x)

What is the derivative of x^2-2xy ?
The derivative of x^2-2xy is 2x-2(y+x(dy)/(dx))
What is the first derivative of x^2-2xy ?
The first derivative of x^2-2xy is 2x-2(y+x(dy)/(dx))