What is the derivative of (2x-1sin(x-2)) ?

The derivative of (2x-1sin(x-2)) is 2sin(x-2)+cos(x-2)(2x-1)

What is the first derivative of (2x-1sin(x-2)) ?

The first derivative of (2x-1sin(x-2)) is 2sin(x-2)+cos(x-2)(2x-1)

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\frac{d}{d x} ((2 x - 1) sin (x - 2))

2 sin (x - 2) + cos (x - 2) (2 x - 1)

Solution steps

\frac{d}{d x} ((2 x - 1) sin (x - 2))

Apply the Product Rule:

(f \cdot g)^{'} = f^{'} \cdot g + f \cdot g^{'}

f = 2 x - 1, g = sin (x - 2)

= \frac{d}{d x} (2 x - 1) sin (x - 2) + \frac{d}{d x} (sin (x - 2)) (2 x - 1)

\frac{d}{d x} (2 x - 1) = 2

\frac{d}{d x} (sin (x - 2)) = cos (x - 2)

= 2 sin (x - 2) + cos (x - 2) (2 x - 1)

y = \frac{5}{ln ( x )}

f^{^{''}} (x) = e^{x}

\int x^{3} e^{5 x} d x

1 - 2 e^{- 2 t} + e^{- 4 t}

\int \frac{1}{16 - 81 x ^{2}} d x

What is the derivative of (2x-1sin(x-2)) ?
The derivative of (2x-1sin(x-2)) is 2sin(x-2)+cos(x-2)(2x-1)
What is the first derivative of (2x-1sin(x-2)) ?
The first derivative of (2x-1sin(x-2)) is 2sin(x-2)+cos(x-2)(2x-1)