What is the integral from-3 to 3 of 1/2 (81-x^4) ?

The integral from-3 to 3 of 1/2 (81-x^4) is 972/5

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

integral from-3 to 3 of 1/2 (81-x^4)

\int_{- 3}^{3} \frac{1}{2} (81 - x^{4}) d x

\frac{972}{5}

Decimal Notation

194.4

Solution steps

\int_{- 3}^{3} \frac{1}{2} (81 - x^{4}) d x

Take the constant out:

\int a \cdot f (x) d x = a \cdot \int f (x) d x

= \frac{1}{2} \cdot \int_{- 3}^{3} 81 - x^{4} d x

Apply the Sum Rule:

\int f (x) \pm g (x) d x = \int f (x) d x \pm \int g (x) d x

= \frac{1}{2} (\int_{- 3}^{3} 81 d x - \int_{- 3}^{3} x^{4} d x)

\int_{- 3}^{3} 81 d x = 486

\int_{- 3}^{3} x^{4} d x = \frac{486}{5}

= \frac{1}{2} (486 - \frac{486}{5})

Simplify

\frac{1}{2} (486 - \frac{486}{5}) : \frac{972}{5}

= \frac{972}{5}

\frac{d}{d x} (25 x^{2} - 1)

x \to \frac{π}{4} lim (tan^{t a n (2 x)} (x))

f (x) = sin (5 ln (x))

\frac{d v}{d v}

x \to 0 + lim (x^{19 x})

What is the integral from-3 to 3 of 1/2 (81-x^4) ?
The integral from-3 to 3 of 1/2 (81-x^4) is 972/5