What is the integral of (sin(x)-4)/(cos(x)) ?

The integral of (sin(x)-4)/(cos(x)) is -ln|cos(x)|-4ln|tan(x)+sec(x)|+C

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integral of (sin(x)-4)/(cos(x))

\int \frac{sin ( x ) - 4}{cos ( x )} d x

- ln ∣ cos (x) ∣ - 4 ln ∣ tan (x) + sec (x) ∣ + C

Solution steps

\int \frac{sin ( x ) - 4}{cos ( x )} d x

Expand

\frac{sin ( x ) - 4}{cos ( x )} : \frac{sin ( x )}{cos ( x )} - \frac{4}{cos ( x )}

= \int \frac{sin ( x )}{cos ( x )} - \frac{4}{cos ( x )} d x

Apply the Sum Rule:

\int f (x) \pm g (x) d x = \int f (x) d x \pm \int g (x) d x

= \int \frac{sin ( x )}{cos ( x )} d x - \int \frac{4}{cos ( x )} d x

\int \frac{sin ( x )}{cos ( x )} d x = - ln ∣ cos (x) ∣

\int \frac{4}{cos ( x )} d x = 4 ln ∣ tan (x) + sec (x) ∣

= - ln ∣ cos (x) ∣ - 4 ln ∣ tan (x) + sec (x) ∣

Add a constant to the solution

= - ln ∣ cos (x) ∣ - 4 ln ∣ tan (x) + sec (x) ∣ + C

\int \frac{sin ^{2} ( x )}{x} d x

\int e^{- 2 y} d y

\frac{d}{d x} (900 x - \frac{1}{3} x^{3} + 2500)

\int \frac{- x + 1}{x ^{2} + x + 1} d x

5 y^{^{''}} + 5 y^{^{'}} - 10 y = 0

What is the integral of (sin(x)-4)/(cos(x)) ?
The integral of (sin(x)-4)/(cos(x)) is -ln|cos(x)|-4ln|tan(x)+sec(x)|+C