What is the integral from 0 to 4 of 3/(x^2) ?

The integral from 0 to 4 of 3/(x^2) is diverges

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integral from 0 to 4 of 3/(x^2)

\int_{0}^{4} \frac{3}{x ^{2}} d x

diverges

Solution steps

\int_{0}^{4} \frac{3}{x ^{2}} d x

Take the constant out:

\int a \cdot f (x) d x = a \cdot \int f (x) d x

= 3 \cdot \int_{0}^{4} \frac{1}{x ^{2}} d x

Apply the Power Rule

= 3 [- \frac{1}{x}]_{0}^{4}

Compute the boundaries:

diverges

= diverges

\frac{d ^{2}}{d x ^{2}} (5 e^{x})

f (x) = 5 x^{2} - 4 x + 3

y^{^{''}} = k^{2} \cdot y

\int 5 e^{- x} d x

y^{^{'}} - 4 x y = 0

What is the integral from 0 to 4 of 3/(x^2) ?
The integral from 0 to 4 of 3/(x^2) is diverges