What is the solution for cos^2(x)sin(x)y^'+(cos^3(x))y=1 ?

The solution for cos^2(x)sin(x)y^'+(cos^3(x))y=1 is y=(tan(x))/(sin(x))+(c_{1})/(sin(x))

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cos^2(x)sin(x)y^'+(cos^3(x))y=1

cos^{2} (x) sin (x) y^{^{'}} + (cos^{3} (x)) y = 1

y = \frac{tan ( x )}{sin ( x )} + \frac{c _{1}}{sin ( x )}

Solution steps

cos^{2} (x) sin (x) y^{'} (x) + (cos^{3} (x)) y = 1

Solve linear ODE:

y = \frac{tan ( x )}{sin ( x )} + \frac{c _{1}}{sin ( x )}

y = \frac{tan ( x )}{sin ( x )} + \frac{c _{1}}{sin ( x )}

(4 x^{2} + 5) (3 x - 2)

x \to 4 lim (\frac{a x ^{3}}{x - 4})

\frac{d y}{d x} = (x y)^{\frac{1}{3}}, y (2) = 1

\frac{d}{d x} (7 x e^{- 9 x})

f (x) = - sin (2 x)

What is the solution for cos^2(x)sin(x)y^'+(cos^3(x))y=1 ?
The solution for cos^2(x)sin(x)y^'+(cos^3(x))y=1 is y=(tan(x))/(sin(x))+(c_{1})/(sin(x))