What is (\partial)/(\partial x)(9sin(xy)) ?

The answer to (\partial)/(\partial x)(9sin(xy)) is 9cos(xy)y

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(\partial)/(\partial x)(9sin(xy))

\frac{\partial}{\partial x} (9 sin (x y))

9 cos (x y) y

Solution steps

\frac{\partial}{\partial x} (9 sin (x y))

Treat

y

as a constant

Take the constant out:

(a \cdot f)^{'} = a \cdot f^{'}

= 9 \frac{\partial}{\partial x} (sin (x y))

Apply the chain rule:

cos (x y) \frac{\partial}{\partial x} (x y)

= cos (x y) \frac{\partial}{\partial x} (x y)

\frac{\partial}{\partial x} (x y) = y

= 9 cos (x y) y

\int - 2 tan^{2} (x) d x

\frac{\partial}{\partial x} (x y^{2} + x^{2} y)

x \to 0 + lim ((2 x)^{3 x})

y = \frac{x ^{2} - 1}{x ^{2} + x + 1}

\int \frac{x ^{2} + 2 x - 1}{x ( x + 2 ) ( 2 x - 1 )} d x

What is (\partial)/(\partial x)(9sin(xy)) ?
The answer to (\partial)/(\partial x)(9sin(xy)) is 9cos(xy)y