What is the tangent of y=x^2-3,(5,22) ?

The tangent of y=x^2-3,(5,22) is y=10x-28

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tangent of y=x^2-3,(5,22)

tangent of

y = x^{2} - 3, (5, 22)

y = 10 x - 28

Solution steps

Find the slope of

y = x^{2} - 3 : \frac{d y}{d x} = 2 x

EN : T i tl e G e n er a l Eq u a t i o n Sl o p e A t P o in t 2 Eq : m = 10

Find the line with slope m=

10

and passing through

(5, 22) : y = 10 x - 28

y = 10 x - 28

\int \frac{x ^{5}}{e ^{x^{6}}} d x

x \to 0 lim (\frac{sin ( 3 x )}{tan ( 10 x )})

y^{^{''}} + 6 y^{^{'}} + 18 y = 0, y (\frac{π}{2}) = 0, y^{^{'}} (\frac{π}{2}) = 6

\frac{d}{d x} (5 x^{2} (x - 5)^{4})

\frac{d ^{2}}{d x ^{2}} (x^{\frac{1}{10}})

What is the tangent of y=x^2-3,(5,22) ?
The tangent of y=x^2-3,(5,22) is y=10x-28