What is the integral of cos(5x)x ?

The integral of cos(5x)x is 1/25 (5xsin(5x)+cos(5x))+C

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integral of cos(5x)x

\int cos (5 x) x d x

\frac{1}{25} (5 x sin (5 x) + cos (5 x)) + C

Solution steps

\int cos (5 x) x d x

Apply u-substitution

: \int \frac{u cos ( u )}{25} d u

= \int \frac{u cos ( u )}{25} d u

Take the constant out:

\int a \cdot f (x) d x = a \cdot \int f (x) d x

= \frac{1}{25} \cdot \int u cos (u) d u

Apply Integration By Parts

: u sin (u) - \int sin (u) d u

= \frac{1}{25} (u sin (u) - \int sin (u) d u)

\int sin (u) d u = - cos (u)

= \frac{1}{25} (u sin (u) - (- cos (u)))

Substitute back

u = 5 x

= \frac{1}{25} (5 x sin (5 x) - (- cos (5 x)))

Simplify

= \frac{1}{25} (5 x sin (5 x) + cos (5 x))

Add a constant to the solution

= \frac{1}{25} (5 x sin (5 x) + cos (5 x)) + C

x \to 0 lim (\frac{ln ( x ^{2} )}{x})

\frac{\partial}{\partial s} (ln (1 + s^{2} + t^{2}))

\int \frac{1}{z ^{3} z ^{2} - 9} d z

x \to 3 lim (- \frac{5}{8} \cdot x^{4})

y = x^{2} - 6 x, y = - x^{2} + 4 x

What is the integral of cos(5x)x ?
The integral of cos(5x)x is 1/25 (5xsin(5x)+cos(5x))+C