en

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

y^'=-50ky+k

Solution

y^{^{'}} = - 50 k y + k

Solution

y = \frac{e ^{- 50 k t - c_{1}}}{50} + \frac{1}{50}

Solution steps

y^{'} (t) = - 50 k y (t) + k

Solve separable ODE:

y = \frac{e ^{- 50 k t - c_{1}}}{50} + \frac{1}{50}

y = \frac{e ^{- 50 k t - c_{1}}}{50} + \frac{1}{50}

Graph

Popular Examples

taylor cos(θ)taylor

cos (θ)

integral from 0 to 2 of-t^3

\int_{0}^{2} - t^{3} d t

integral of (2x^3+3x)/((x^4+3x^2+7)^4)

\int \frac{2 x ^{3} + 3 x}{( x ^{4} + 3 x ^{2} + 7 ) ^{4}} d x

integral from 1 to 2 of (1+2y)^2

\int_{1}^{2} (1 + 2 y)^{2} d y

integral of sin^3(8x)cos^{-2}(8x)

\int sin^{3} (8 x) cos^{- 2} (8 x) d x

Frequently Asked Questions (FAQ)

What is the solution for y^'=-50ky+k ?
The solution for y^'=-50ky+k is y=(e^{-50kt-c_{1}})/(50)+1/50