What is the derivative of x^4-4x^2+3 ?

The derivative of x^4-4x^2+3 is 4x^3-8x

What is the first derivative of x^4-4x^2+3 ?

The first derivative of x^4-4x^2+3 is 4x^3-8x

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\frac{d}{d x} (x^{4} - 4 x^{2} + 3)

4 x^{3} - 8 x

Solution steps

\frac{d}{d x} (x^{4} - 4 x^{2} + 3)

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d x} (x^{4}) - \frac{d}{d x} (4 x^{2}) + \frac{d}{d x} (3)

\frac{d}{d x} (x^{4}) = 4 x^{3}

\frac{d}{d x} (4 x^{2}) = 8 x

\frac{d}{d x} (3) = 0

= 4 x^{3} - 8 x + 0

Simplify

= 4 x^{3} - 8 x

\frac{23}{( 8 x - 1 ) ^{2}}

x^{7}

\int \frac{cos ( 3 x )}{sin ^{2} ( 3 x )} d x

x e^{x}, 1 \leq x \leq 7

What is the derivative of x^4-4x^2+3 ?
The derivative of x^4-4x^2+3 is 4x^3-8x
What is the first derivative of x^4-4x^2+3 ?
The first derivative of x^4-4x^2+3 is 4x^3-8x