What is the derivative of 1/(2x+2x) ?

The derivative of 1/(2x+2x) is -1/(2x^2)+2

What is the first derivative of 1/(2x+2x) ?

The first derivative of 1/(2x+2x) is -1/(2x^2)+2

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\frac{d}{d x} (\frac{1}{2 x} + 2 x)

- \frac{1}{2 x ^{2}} + 2

Solution steps

\frac{d}{d x} (\frac{1}{2 x} + 2 x)

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d x} (\frac{1}{2 x}) + \frac{d}{d x} (2 x)

\frac{d}{d x} (\frac{1}{2 x}) = - \frac{1}{2 x ^{2}}

\frac{d}{d x} (2 x) = 2

= - \frac{1}{2 x ^{2}} + 2

\int_{4}^{9} \frac{1}{7 - x} d x

\frac{d y}{d x} = e^{6 x} + 12 y

(\frac{1}{2 x + 3})^{3}

(- 1.2) (5.5)

\frac{d}{d x} (sin (\frac{π x}{11}))

What is the derivative of 1/(2x+2x) ?
The derivative of 1/(2x+2x) is -1/(2x^2)+2
What is the first derivative of 1/(2x+2x) ?
The first derivative of 1/(2x+2x) is -1/(2x^2)+2