What is the derivative of (4x-8^2) ?

The derivative of (4x-8^2) is 8(4x-8)

What is the first derivative of (4x-8^2) ?

The first derivative of (4x-8^2) is 8(4x-8)

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\frac{d}{d x} ((4 x - 8)^{2})

8 (4 x - 8)

Solution steps

\frac{d}{d x} ((4 x - 8)^{2})

Apply the chain rule:

2 (4 x - 8) \frac{d}{d x} (4 x - 8)

= 2 (4 x - 8) \frac{d}{d x} (4 x - 8)

\frac{d}{d x} (4 x - 8) = 4

= 2 (4 x - 8) \cdot 4

Simplify

= 8 (4 x - 8)

\int_{0}^{x} 3 e^{- 3 x} d x

x \to \infty lim (13 x)

\int x^{9} x^{5} + 7 d x

\int \frac{x ^{2} - 8}{x + 3} d x

\frac{x ^{2} - 25}{x - 5}

What is the derivative of (4x-8^2) ?
The derivative of (4x-8^2) is 8(4x-8)
What is the first derivative of (4x-8^2) ?
The first derivative of (4x-8^2) is 8(4x-8)