What is the limit as s approaches 5 of 5/((s-5)^2) ?

The limit as s approaches 5 of 5/((s-5)^2) is infinity

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

limit as s approaches 5 of 5/((s-5)^2)

s \to 5 lim (\frac{5}{( s - 5 ) ^{2}})

\infty

Solution steps

s \to 5 lim (\frac{5}{( s - 5 ) ^{2}})

x \to a - lim f (x) = x \to a + lim f (x) = L

then

x \to a lim f (x) = L

s \to 5 - lim (\frac{5}{( s - 5 ) ^{2}}) = \infty

s \to 5 + lim (\frac{5}{( s - 5 ) ^{2}}) = \infty

= \infty

\frac{d}{d x} (sin (2^{1 + \frac{1}{x}}))

\frac{d}{d x} (2 - ln (x))

\int \frac{( ln ( x ) ) ^{n}}{x} d x

y = x^{2} - x + 7, at x = 2

\int_{- 2}^{2} \frac{1}{36 + x ^{2}} d x

What is the limit as s approaches 5 of 5/((s-5)^2) ?
The limit as s approaches 5 of 5/((s-5)^2) is infinity