What is the tangent of f(x)= 1/(5+3x),(-1, 1/2) ?

The tangent of f(x)= 1/(5+3x),(-1, 1/2) is y=-3/4 x-1/4

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tangent of f(x)= 1/(5+3x),(-1, 1/2)

tangent of

f (x) = \frac{1}{5 + 3 x}, (- 1, \frac{1}{2})

y = - \frac{3}{4} x - \frac{1}{4}

Solution steps

Find the slope of

f (x) = \frac{1}{5 + 3 x} : \frac{df ( x )}{d x} = - \frac{3}{( 5 + 3 x ) ^{2}}

EN : T i tl e G e n er a l Eq u a t i o n Sl o p e A t P o in t 2 Eq : m = - \frac{3}{4}

Find the line with slope m=

- \frac{3}{4}

and passing through

(- 1, \frac{1}{2}) : y = - \frac{3}{4} x - \frac{1}{4}

y = - \frac{3}{4} x - \frac{1}{4}

\frac{d}{d x} (π 5 x cos (x))

\frac{d}{d x} (C e^{x})

\frac{\partial}{\partial x} (y ln (x^{2} + y^{2} + 4))

\frac{d}{d x} (x^{3} - \frac{3}{x} + e^{2})

\int (cos^{2} (x) \cdot sin (x)) d x

What is the tangent of f(x)= 1/(5+3x),(-1, 1/2) ?
The tangent of f(x)= 1/(5+3x),(-1, 1/2) is y=-3/4 x-1/4