What is the solution for y^'+((x-2))/(x-1)y=0 ?

The solution for y^'+((x-2))/(x-1)y=0 is y=e^{-x+c_{1}}x-e^{-x+c_{1}}

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y^'+((x-2))/(x-1)y=0

y^{^{'}} + \frac{( x - 2 )}{x - 1} y = 0

y = e^{- x + c_{1}} x - e^{- x + c_{1}}

Solution steps

y^{'} (x) + \frac{( x - 2 )}{x - 1} y = 0

Solve separable ODE:

y = e^{- x + c_{1}} x - e^{- x + c_{1}}

y = e^{- x + c_{1}} x - e^{- x + c_{1}}

\frac{d}{d x} (x^{2} \cdot ln (2 x))

\frac{s}{s ^{2} + 25}

\int_{0}^{\frac{π}{3}} sin^{4} (3 x) d x

ln (\frac{x + 3}{x - 1})

121 y^{^{''}} - 16 y = 0

What is the solution for y^'+((x-2))/(x-1)y=0 ?
The solution for y^'+((x-2))/(x-1)y=0 is y=e^{-x+c_{1}}x-e^{-x+c_{1}}