What is (\partial)/(\partial x)(sin(x)+cos(y)) ?

The answer to (\partial)/(\partial x)(sin(x)+cos(y)) is cos(x)

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(\partial)/(\partial x)(sin(x)+cos(y))

\frac{\partial}{\partial x} (sin (x) + cos (y))

cos (x)

Solution steps

\frac{\partial}{\partial x} (sin (x) + cos (y))

Treat

y

as a constant

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{\partial}{\partial x} (sin (x)) + \frac{\partial}{\partial x} (cos (y))

\frac{\partial}{\partial x} (sin (x)) = cos (x)

\frac{\partial}{\partial x} (cos (y)) = 0

= cos (x) + 0

Simplify

= cos (x)

f (x) = \frac{x ^{3}}{x - 1}

n = 0 \sum \infty (\frac{2}{7})^{\frac{n}{2}}

y^{^{'''}} + 2 y^{^{''}} - y^{^{'}} - 2 y = 0

(1 - cos (t))^{^{'}}

\int_{0}^{2} 1 + 16 x^{2} d x

What is (\partial)/(\partial x)(sin(x)+cos(y)) ?
The answer to (\partial)/(\partial x)(sin(x)+cos(y)) is cos(x)