What is the derivative of 4x-sin(2x) ?

The derivative of 4x-sin(2x) is 4-cos(2x)*2

What is the first derivative of 4x-sin(2x) ?

The first derivative of 4x-sin(2x) is 4-cos(2x)*2

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\frac{d}{d x} (4 x - sin (2 x))

4 - cos (2 x) \cdot 2

Solution steps

\frac{d}{d x} (4 x - sin (2 x))

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d x} (4 x) - \frac{d}{d x} (sin (2 x))

\frac{d}{d x} (4 x) = 4

\frac{d}{d x} (sin (2 x)) = cos (2 x) \cdot 2

= 4 - cos (2 x) \cdot 2

- 3 cot (x) csc (x)

\int e^{x^{2}} \cdot x ln (x) d x

y^{^{'}} + \frac{3 y}{100 - x} = \frac{4}{5}

\int \frac{tan ^{3} ( ln ( x ) )}{4 x} d x

\int t cos^{2} (t) d t

What is the derivative of 4x-sin(2x) ?
The derivative of 4x-sin(2x) is 4-cos(2x)*2
What is the first derivative of 4x-sin(2x) ?
The first derivative of 4x-sin(2x) is 4-cos(2x)*2