What is the derivative of f(x)=(ln(x))^2 ?

The derivative of f(x)=(ln(x))^2 is (2ln(x))/x

What is the first derivative of f(x)=(ln(x))^2 ?

The first derivative of f(x)=(ln(x))^2 is (2ln(x))/x

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derivative of

f (x) = (ln (x))^{2}

\frac{2 ln ( x )}{x}

Solution steps

\frac{d}{d x} ((ln (x))^{2})

Apply the chain rule:

2 ln (x) \frac{d}{d x} (ln (x))

= 2 ln (x) \frac{d}{d x} (ln (x))

\frac{d}{d x} (ln (x)) = \frac{1}{x}

= 2 ln (x) \frac{1}{x}

Simplify

2 ln (x) \frac{1}{x} : \frac{2 ln ( x )}{x}

= \frac{2 ln ( x )}{x}

y^{^{''}} - 4 y = e^{2 t}

\int_{\frac{1}{2}}^{3} 8 x ln (2 x) d x

t \to 0 lim (\frac{( tan ( t ) sec ( 2 t ) )}{3 t})

\frac{\partial}{\partial y} (x e^{x y} - 2 y + 1)

ln (x)

What is the derivative of f(x)=(ln(x))^2 ?
The derivative of f(x)=(ln(x))^2 is (2ln(x))/x
What is the first derivative of f(x)=(ln(x))^2 ?
The first derivative of f(x)=(ln(x))^2 is (2ln(x))/x