What is the derivative of f(x)=(ln(x))^2 ?

The derivative of f(x)=(ln(x))^2 is (2ln(x))/x

What is the first derivative of f(x)=(ln(x))^2 ?

The first derivative of f(x)=(ln(x))^2 is (2ln(x))/x

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derivative of

f (x) = (ln (x))^{2}

\frac{2 ln ( x )}{x}

Solution steps

\frac{d}{d x} ((ln (x))^{2})

Apply the chain rule:

2 ln (x) \frac{d}{d x} (ln (x))

= 2 ln (x) \frac{d}{d x} (ln (x))

\frac{d}{d x} (ln (x)) = \frac{1}{x}

= 2 ln (x) \frac{1}{x}

Simplify

2 ln (x) \frac{1}{x} : \frac{2 ln ( x )}{x}

= \frac{2 ln ( x )}{x}

f (x) = - tan^{2} (x)

y^{^{''}} - 4 y = e^{2 t}

3 x^{2} ln (7 x)

x y^{^{'}} + 2 y = x + 2

\int \frac{1}{tan ^{2} ( θ )} sec^{2} (θ) d θ

What is the derivative of f(x)=(ln(x))^2 ?
The derivative of f(x)=(ln(x))^2 is (2ln(x))/x
What is the first derivative of f(x)=(ln(x))^2 ?
The first derivative of f(x)=(ln(x))^2 is (2ln(x))/x