What is the integral of 1/(tan^2(θ))sec^2(θ) ?

The integral of 1/(tan^2(θ))sec^2(θ) is -cot(θ)+C

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integral of 1/(tan^2(θ))sec^2(θ)

\int \frac{1}{tan ^{2} ( θ )} sec^{2} (θ) d θ

- cot (θ) + C

Solution steps

\int \frac{1}{tan ^{2} ( θ )} sec^{2} (θ) d θ

Simplify

\frac{1}{tan ^{2} ( θ )} sec^{2} (θ) : csc^{2} (θ)

= \int csc^{2} (θ) d θ

Use the common integral:

\int csc^{2} (θ) d θ = - cot (θ)

= - cot (θ)

Add a constant to the solution

= - cot (θ) + C

25 - x^{2}, x^{2} - 25, - 5, 5

\int sec^{2} (\frac{x}{a}) d x

\int_{\frac{1}{2}}^{3} 8 x ln (2 x) d x

r \frac{d y}{d r} = y^{2} + 1

t \to 0 lim (\frac{( tan ( t ) sec ( 2 t ) )}{3 t})

What is the integral of 1/(tan^2(θ))sec^2(θ) ?
The integral of 1/(tan^2(θ))sec^2(θ) is -cot(θ)+C