What is the integral from-infinity to 0 of xe^{-7x} ?

The integral from-infinity to 0 of xe^{-7x} is diverges

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integral from-infinity to 0 of xe^{-7x}

\int_{- \infty}^{0} x e^{- 7 x} d x

diverges

Solution steps

\int_{- \infty}^{0} x e^{- 7 x} d x

Compute the indefinite integral:

\int x e^{- 7 x} d x = \frac{1}{49} (- 7 e^{- 7 x} x - e^{- 7 x}) + C

Compute the boundaries:

\int_{- \infty}^{0} x e^{- 7 x} d x =

diverges

= diverges

f (x) = 2 x ln (x)

- 2 x sin (x^{2})

x \to 15 + lim (15 x - 15)

\int sin (x) \cdot cos (2 x) d x

\frac{d}{d x} (arcsin^{4} (x^{7} y^{2} + \frac{z}{x ^{3}}))

What is the integral from-infinity to 0 of xe^{-7x} ?
The integral from-infinity to 0 of xe^{-7x} is diverges